(x^2+3x-20)=(x^2-2x+60)

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Solution for (x^2+3x-20)=(x^2-2x+60) equation:


Simplifying
(x2 + 3x + -20) = (x2 + -2x + 60)

Reorder the terms:
(-20 + 3x + x2) = (x2 + -2x + 60)

Remove parenthesis around (-20 + 3x + x2)
-20 + 3x + x2 = (x2 + -2x + 60)

Reorder the terms:
-20 + 3x + x2 = (60 + -2x + x2)

Remove parenthesis around (60 + -2x + x2)
-20 + 3x + x2 = 60 + -2x + x2

Add '-1x2' to each side of the equation.
-20 + 3x + x2 + -1x2 = 60 + -2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-20 + 3x + 0 = 60 + -2x + x2 + -1x2
-20 + 3x = 60 + -2x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-20 + 3x = 60 + -2x + 0
-20 + 3x = 60 + -2x

Solving
-20 + 3x = 60 + -2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2x' to each side of the equation.
-20 + 3x + 2x = 60 + -2x + 2x

Combine like terms: 3x + 2x = 5x
-20 + 5x = 60 + -2x + 2x

Combine like terms: -2x + 2x = 0
-20 + 5x = 60 + 0
-20 + 5x = 60

Add '20' to each side of the equation.
-20 + 20 + 5x = 60 + 20

Combine like terms: -20 + 20 = 0
0 + 5x = 60 + 20
5x = 60 + 20

Combine like terms: 60 + 20 = 80
5x = 80

Divide each side by '5'.
x = 16

Simplifying
x = 16

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